# SOLUTION: 1. two parallel lines touch the circle at points A and B respectively. if area of the circle is 25pie cm2. then AB is equal to? 2. Area of the greatest circle of the circles con

Algebra ->  -> SOLUTION: 1. two parallel lines touch the circle at points A and B respectively. if area of the circle is 25pie cm2. then AB is equal to? 2. Area of the greatest circle of the circles con      Log On

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 Question 557774: 1. two parallel lines touch the circle at points A and B respectively. if area of the circle is 25pie cm2. then AB is equal to? 2. Area of the greatest circle of the circles constructed on the side of a right triangle, taking these sides as diameters, if the two smalles sides are 1.5cm and 2cm. Answer by mananth(13127)   (Show Source): You can put this solution on YOUR website!Area = 25 pi cm^2 AB are on lines parallel to each other so AB is the diameter Area = pi*r^2 25 pi = pir^2 r^2=25 r= 5 cm AB = 10 cm ------------- Hypotenuse ^2= leg1^2+leg2^2 leg1 = 1.5 cm Leg2^2= 2 cm Hypotenuse^2 1.5 ^2 + 2 ^2 Hypotenuse^2 2.25 + 4 Hypotenuse^2 6.25 take the square root Hypotenuse^2 2.5 cm the diameter of the circle = 2.5 cm radius = 1.25 Area of circle = pi*r^2 Area =pi*1.25^2 Area = 4.90 cm^2 ----------