# SOLUTION: Given the equation of the circle (x – 9)² + y² = 484, the center of the circle is located at __________, and its radius has a length of __________ units.

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 Click here to see ALL problems on Circles Question 456656: Given the equation of the circle (x – 9)² + y² = 484, the center of the circle is located at __________, and its radius has a length of __________ units.Answer by Edwin McCravy(9717)   (Show Source): You can put this solution on YOUR website!The general statement for all circles is: Given the equation of the circle (x – h)² + (y-k)² = r², the center of the circle is located at (h,k), and its radius has a length of r units. You should learn that. Your equation is (x – 9)² + y² = 484 Since the square root of 484 is 22 and since y can be written as (y - 0), your equation can be written as (x – 9)² + (y - 0)² = 22² Now if we compare that with (x – h)² + (y - k)² = r² we see that h = 9, k = 0, and r = 22. So we make those substitutions in the general statement about all circles, we get Given the equation of the circle (x – 9)² + (y - 0)² = 22², the center of the circle is located at (9,0), and its radius has a length of 22 units. Edwin