Questions on Geometry: Circles and their properties answered by real tutors!

Algebra ->  Algebra -> Questions on Geometry: Circles and their properties answered by real tutors!     (Log On)
Ad: Algebra Solved!™: algebra software that solves YOUR algebra homework problems with step-by-step help!



Question 143914: The center of circle P is at (8,6) and (13, 6 - sqrt39) is a point on the circle. If circle P is inscribed in square ABCD, what is the area of ABCD?: The center of circle P is at (8,6) and (13, 6 - sqrt39) is a point on the circle. If circle P is inscribed in square ABCD, what is the area of ABCD?
Answer by solver91311(1877) About Me  (Show Source):
You can put this solution on YOUR website!
Given the center of a circle and a point on the circle, you can use the distance formula d=sqrt( (x[1]-x[2])^2 + (y[1]-y[2])^2) to calculate the radius. The diameter of a circle inscribed in a square is equal to the side length of the square. So, take the radius that you calculated, double it, and then square the result for the area of the square.