SOLUTION: Hi there! I am not very good at math and I have been stuck on this question for 20 minutes now. The question is: calculate the volume of a box to hold a sphere-shaped beaker with a

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Question 953226: Hi there! I am not very good at math and I have been stuck on this question for 20 minutes now. The question is: calculate the volume of a box to hold a sphere-shaped beaker with a volume of 413cm^3. The second part is : how much space is being occupied by the beaker and how much is being wasted, in percents.
Thank you so much, I honestly have no idea what to do.

Found 2 solutions by macston, josmiceli:
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
Volume of sphere=
Multiply each side by


Find the cube root of each side.
4.62cm=r
The cubic box to hold the sphere must have edges=2r (diameter of the sphere)
The volume of the cube ===
Volume of cube=789 cm^3
Volume wasted=vol(cube)-vol(sphere)=789cm^3-413cm^3=376cm^3
Percent of cube volume wasted=vol(wasted)/vol(cube)=(376cm^3/789cm^3)(100%)=47.7%

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
The volume of a sphere is:

where is the radius
-----------------------
You are given that:
cm3
---------------------

Multiply both sides by

Divide both sides by



---------------
check:




This looks close enough
-----------------------
If this sphere is tightly enclosed in a cube,
the volume of the box is
This is because is equal to a side
of the box
-----------------



----------------------

( wasted volume in cm3 )
-------------------------
You are asked for:
which is a %


47.64% is wasted space inside the cube
----------------
Hope I got it -tough calculations



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