SOLUTION: how many square feet of aluminum materials will be needed in order to construct an open top right cylindrical tank which is 6 feet high and has a diameter of 2 feet,if only 5% of t

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Question 609005: how many square feet of aluminum materials will be needed in order to construct an open top right cylindrical tank which is 6 feet high and has a diameter of 2 feet,if only 5% of the total surface of the cylinder is to be allowed for waste?.please help.please give solution or steps.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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how many square feet of aluminum materials will be needed in order to construct an open top right cylindrical tank which is 6 feet high and has a diameter of 2 feet, if only 5% of the total surface of the cylinder is to be allowed for waste?
:
The equation for the surface area of an open top cylinder
S.A. = 2pi%2Ar%2Ah + pi%2Ar%5E2
:
However the round bottom will be cut out of a 2 by 2 ft square, which would have some waste.
The side would be a rectangle so no waste there.
:
This cylinder will have a radius of half the diameter (1 ft) and a height of 6 ft
S.a. = side + square for the bottom
S.A. = 2pi%2A1%2A6 + 2^2
S.A. = 12pi+%2B+4
S.A. = 37.7 + 4
S.A. = 41.7 sq/ft required
:
Waste from the round bottom: 4 - pi%2A1%5E2 = .86 sq/ft wasted
.86%2F41.7 *100 ~ 2% wasted