SOLUTION: A sphere circumscribes a right circular cylinder of altitude 9 cm and diameter 7 cm, find the ratio of their (a) volumes (b) total surfaces areas.

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Question 1189062: A sphere circumscribes a right circular cylinder of altitude 9 cm and diameter 7 cm, find the ratio of their (a) volumes (b) total surfaces areas.
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
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Cylinder has height 9 cm and radius 3.5 cm and therefore volume of πr^2h=110.25π cm^3
the sphere's radius goes from the center to one side of the cylinder at the edge. In that triangle, the hypotenuse is the radius of the sphere, one side is the radius of the cylinder, 3.5 cm, and the other side is half the elevation, or 4.5 cm Therefore, the radius of the sphere is sqrt (3.5^2+4.5^2)=5.701 cm, and the volume is (4/3)π*5.701^3=247.04π cm^3
This makes the c/s ratio 110.25π/247.05π=0.4463
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area of the cylinder is 2πrh+2πr^2h=7*9*π+220.5π=283.5π
area of sphere is 4πr^2=4*5.701^2*π=130.01π cm^2
That ratio of c/s=2.181

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