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A HOLLOW metal sphere 45cm in diameter is as a float. If the metal sphere sinks of the depth of 15cm,
what is the area of the wetted surface?
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Use the formula for the surface area of a spherical cap
A = ,
where pi = 3.14159..., R is the sphere radius (45 cm), h is the depth of the spherical cap (15 cm).
According to the formula, the wetted area of the sphere is
A = 2*3.14159*45*15 = 4241.1465 cm^2 ANSWER
Solved.
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For the area of a spherical segment, see these Internet sources
https://en.wikipedia.org/wiki/Spherical_segment
https://mathworld.wolfram.com/Zone.html
https://www.math10.com/en/geometry/sphere.html