You can
put this solution on YOUR website!Let's start with the appropriate formulas for the volumes of the given solids.
Cylinder:
![V[c] = (pi)r^2h](/cgi-bin/plot-formula.mpl?expression=V%5Bc%5D+=+%28pi%29r%5E2h&x=0003)
but the height of the cylinder is given as the length of the diameter (D) of its base and D = 2r where r is the radius of the base. So we can express the volume of the cylinder entirely in terms of the radius (r) of its base, right?
![V[c] = (pi)r^2(2r)](/cgi-bin/plot-formula.mpl?expression=V%5Bc%5D+=+%28pi%29r%5E2%282r%29&x=0003)
Simplifying this we get:
![V[c] = 2(pi)r^3](/cgi-bin/plot-formula.mpl?expression=V%5Bc%5D+=+2%28pi%29r%5E3&x=0003)
as the volume of the cylinder.
Sphere:
The largest sphere that could be contained within a cylinder of the dimensions given above i.e., h = 2r and radius r, would be a sphere whose radius is equal to that of the cylinder, or radius r.
The volume of a sphere of radius r is given by:
![V[s] = (4/3)(pi)r^3](/cgi-bin/plot-formula.mpl?expression=V%5Bs%5D+=+%284%2F3%29%28pi%29r%5E3&x=0003)
Now all we have to do is to subtract the volume of the sphere from the volume of the cylinder, or
![V[c]-V[s]](/cgi-bin/plot-formula.mpl?expression=V%5Bc%5D-V%5Bs%5D&x=0003)
to find the amount of material that must be removed from the wooden cylinder to create the largest possible sphere.
![V[c]-V[s] = 2(pi)r^3 - (4/3)(pi)r^3](/cgi-bin/plot-formula.mpl?expression=V%5Bc%5D-V%5Bs%5D+=+2%28pi%29r%5E3+-+%284%2F3%29%28pi%29r%5E3&x=0003)
=