Tutors Answer Your Questions about Average (FREE)
Question 258079: I have to solve this problem by substitution:
2x + y = 6
x= 3y + 10
I begin by using the 2(3y + 10)+ y = 6
Multiply: (6y + 20) + y = 6
add 6y + y to get 7y + 20= 6
-20= 6 -20
7y = -14
7ydivided by 7 = -14 divided by 7
y = -2
put the -2 for the y x = 3 (-2) + 10
x = -6 + 10
x = 4
so my answer would be
(4,-2)
My answer works out when I check my work. Please confirm that my work is correct.
Click here to see answer by Greenfinch(383)  |
Question 258079: I have to solve this problem by substitution:
2x + y = 6
x= 3y + 10
I begin by using the 2(3y + 10)+ y = 6
Multiply: (6y + 20) + y = 6
add 6y + y to get 7y + 20= 6
-20= 6 -20
7y = -14
7ydivided by 7 = -14 divided by 7
y = -2
put the -2 for the y x = 3 (-2) + 10
x = -6 + 10
x = 4
so my answer would be
(4,-2)
My answer works out when I check my work. Please confirm that my work is correct.
Click here to see answer by jim_thompson5910(28503) |
Question 258079: I have to solve this problem by substitution:
2x + y = 6
x= 3y + 10
I begin by using the 2(3y + 10)+ y = 6
Multiply: (6y + 20) + y = 6
add 6y + y to get 7y + 20= 6
-20= 6 -20
7y = -14
7ydivided by 7 = -14 divided by 7
y = -2
put the -2 for the y x = 3 (-2) + 10
x = -6 + 10
x = 4
so my answer would be
(4,-2)
My answer works out when I check my work. Please confirm that my work is correct.
Click here to see answer by scott8148(6628)  |
Question 258846: Hi, I'm trying to help my son with this problem. My answer was 23/30 is that correct?
Simplify: 2/3 +3/10 -2/5
2/3 + 3/10 = 11/30 then that minus 2/5? When I did it on an online math calculator, it said the answer is 17/30. I don't understand how that can be?
Thanks for your help! :)
Click here to see answer by Fombitz(13828)  |
Question 259908: How do you set this word problem up in algebra equation and solve for x?suzy invested part of her 12,000 bonus in fund that paid 10% pfofit and invested the rest in stock that suffered 3% loss find amt of each investment if her overall net profit was 550?
Click here to see answer by stanbon(57231) |
Question 260539: Sarah has gotten scores of 83, 76, and 69 on her first three tests. What score must she get on her fourth test to keep an average of 81 or greater.
fourth test = x
x = (83 + 76 + 69)/3
x = 76
Is this correct?
Click here to see answer by drk(1908) |
Question 261743: you currently have had three test grades with a result of 91, 86, and 89. there is one test left and you want to know what is the lowest grade you can get on this test to have an a average (90%) in the class.How would you translate and solve this problem?
Click here to see answer by richwmiller(9135)  |
Question 261605: Suppose your grades on your first four exams were 84%, 90%, 68%, and 89%. What would be the lowest possible average that your last two exams could have so that your grade in the class, based on the average of the six exams, is at least 78%?
Click here to see answer by checkley77(12569) |
Question 1822: shawn needs to have a 90% average for his exam grade to make an A for the quarter there are three tests in the quarter and his first two exams percentage were 91%,87% what score must he get on the third exam to obtain a 90% average?
90 x 3 = 270
270-87 - 91 = 92
Click here to see answer by ahmad.rakhaa(1) |
Question 266410: Fifteen people took part in a free-throw competition. The first participant scored
x points, the second scored y points, the third scored the arithmetic mean of the
number of points scored by the first two, and each subsequent competitor scored
the arithmetic mean of the number of points scored by all previous ones. How
many points did the last competitor score?
(A) (x+y)/2 (B) 12(x+y)/14 (C) 13(x+y)/15
(D) 14(x+y)/16 (E) none of these
Click here to see answer by user_dude2008(1861) |
Question 267101: Of the 137 students who took a mathematics exam, 94 correctly answered the first question, 69 correctly answered the second question, and 54 correctly answered both questions. How many students did not answer either of the two questions correctly?
Click here to see answer by solver91311(16868)  |
Question 269002: How would you work out this problem; It requires to show all work!
The cafeteria has 360 roses to sell for Valentine's Day. You want to pick
out a perfect red rose for someone special. When you get to the cafeteria
you discover:
*every third rose is too short
*every fourth rose has too many thorns
*every fifth rose is wilted
*every sixth rose is pink
*every eighth rose is yellow
If these are the only problems that the roses have, how many perfect roses are
there for you to choose from?
The problem requires to show all work. I would think that there is an
algebraic expression that would help me out, but I am in need of help.
I can help myself by making pictures to help visualize, but I think there must
be a better way.
Please help me if you can. Thank you!
Click here to see answer by josmiceli(9654)  |
Question 269002: How would you work out this problem; It requires to show all work!
The cafeteria has 360 roses to sell for Valentine's Day. You want to pick
out a perfect red rose for someone special. When you get to the cafeteria
you discover:
*every third rose is too short
*every fourth rose has too many thorns
*every fifth rose is wilted
*every sixth rose is pink
*every eighth rose is yellow
If these are the only problems that the roses have, how many perfect roses are
there for you to choose from?
The problem requires to show all work. I would think that there is an
algebraic expression that would help me out, but I am in need of help.
I can help myself by making pictures to help visualize, but I think there must
be a better way.
Please help me if you can. Thank you!
Click here to see answer by drk(1908) |
Question 270743: You have scored 75,79,78,and 78 in four test out of five tests. You want to score an overall b grade (80). You have the fifth test to pull up your score. How much minimum should you score in the fifth test so that you raise your average to 80(get an overall B grade).
Click here to see answer by stanbon(57231) |
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