SOLUTION: Aldo has scored 84,72,85, and 92 on his previous tests. What score does he need on his next test so that his average (mean) is 85

Question 986479: Aldo has scored 84,72,85, and 92 on his previous tests. What score does he need on his next test so that his average (mean) is 85
Found 2 solutions by solver91311, macston:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Presuming all tests are of equal weight, in order to have a final average of 85 for 5 tests, then the total points scored for all 5 tests must be 85 times 5 or greater. Add up the scores of the first four tests and subtract that total from 85 times 5 to find the score required for the last test.

John

My calculator said it, I believe it, that settles it

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
To average 80 over 5 tests, the sum of the tests scores must be:
(5)(85)=425
.
Aldo's current sum:
84+72+85+92=333
.
Aldo needs:
425-333=92
.
ANSWER: Aldo must score 92 to have an average of 85.
RELATED QUESTIONS
Aldo has scored 83 , 69 , 92 , 92 , and 90 on his previous five tests.... (answered by solver91311,MathLover1)
Chang has scored 87,94 ,89 , and 93 on his previous four tests. What score does he need... (answered by TeishaRenee)
Ryan has scored 74,86 ,75 ,69 and on his previous four tests. What score does he need on... (answered by reviewermath)
Ryan has scored , , , and on his previous four tests. What score does he need on his next (answered by Alan3354)
Manuel has scored 80,64,77 and on his previous three tests. What score does he need on... (answered by persian52)
Keith has scored 84,75,81, and 80 on his previous four tests. What score does he need on... (answered by ewatrrr)
Manuel has scored 76,76, and 90 on his previous three tests. What score does he need on... (answered by ikleyn)
Charlie has scored 89, 78, and 63 on his previous three tests. What score does he need on (answered by ikleyn,greenestamps)
Hello do you know the averafe of: Kevin has scored 72 , 59 , 93 , and 73 on... (answered by Boreal,MathLover1)