SOLUTION: the average of 10 numbers is 68. Two of them ,56 and 32 were remove. find the average of the remaining numbers
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Question 986126: the average of 10 numbers is 68. Two of them ,56 and 32 were remove. find the average of the remaining numbers
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
The sum of 10 numbers that average 68:
(10)(68)=680
Remove two numbers the sum for 8 numbers is:
680-56-32=592
Average of the remaining 8 numbers:
592/8=74
ANSWER: The average of the remaining numbers is 74.
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