SOLUTION: Having issues with this problem, can you help? The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?

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Question 94409: Having issues with this problem, can you help?


The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?
Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
You can put this solution on YOUR website!
Question:
The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?
Answer:

Assume that the first number = x

Four times the first number = 4x

7 more than four times the first = 4x + 7

Given that The second is 7 more than 4 times the first.....

So the second number = 4x + 7

Their sum is given as 112


so we can write,

x + 4x + 7 = 112


==> 5x + 7 = 112

Subtract 7 from both sides...


5x + 7 - 7 = 112 - 7


==> 5x = 105

Divide both sides by 5

==> +5x%2F5+=+105%2F5+


==> x = 21


So the first number is 21


Then the second number is 4x + 7 = 4 * 21 + 7 = 84 + 7 = 91

So the numbers are 91 and 21.

Hope you found the explanation useful.


Regards.

Praseena.