SOLUTION: PLEASE HELP ME IN SOLVING THIS QUESTION RELATED TO GEOMETRIC PROGRESSION....
A SCIENTIST RESEARCHING FERTILIZER CHARTED THE HEIGHT OF A PLANT AS PART OF AN EXPERIMENT.THE HEIGHT W
Algebra.Com
Question 936718: PLEASE HELP ME IN SOLVING THIS QUESTION RELATED TO GEOMETRIC PROGRESSION....
A SCIENTIST RESEARCHING FERTILIZER CHARTED THE HEIGHT OF A PLANT AS PART OF AN EXPERIMENT.THE HEIGHT WAS ORIGINALLY 8 INCHES BUT GREW AT RATE OF 5% PER WEEK AFTER RECEIVING THE EXPERIMENTAL FERTILIZER.WHAT IS THE HEIGHT AFTER 16 WEEKS?
Answer by Danielshinmath(31) (Show Source): You can put this solution on YOUR website!
It would be 8*((1.05)^16) where 8 is the original height, the 1.05 is the 100 percent plus the 5 extra that is grows, then the ^16 is the amount of weeks it grew. On a calculator, it would be approximately 10.72076513 inches
ANSWER: 10.72076513 inches
RELATED QUESTIONS
PLEASE HELP ME IN SOLVING THIS QUESTION IT IS RELATED TO GEOMETRIC PROGRESSION....
SAM... (answered by Danielshinmath)
Pls Help me with this question urgently,thanks. Find the three numbers in a... (answered by Edwin McCravy)
Please help me solve this :
In an geometric progression s1=3 , b2=6
Solve... (answered by Edwin McCravy)
Please help me solve this :
In an geometric progression , b1=3 and b2=6
Solve... (answered by stanbon)
Please help me solve this :
In an geometric progression , s1=3 and s2=6
Solve... (answered by stanbon)
Please help me solve this :
In an geometric progression , b1=3 and b2=6
Calculate... (answered by josgarithmetic)
Please help me solve this :
Determine the product of first three terms of a geometric (answered by Alan3354,ikleyn)
Please help me solve these question, in geometric progression. The first and the last... (answered by robertb)
the 3rd and 4th terms of geometric progression are 12 and 8 respectively.find the sum to... (answered by Boreal)