SOLUTION: How do you show that (8^n+3^n)/(8^-n+3^-n)=24^n without using the logarith way?

Question 913852: How do you show that (8^n+3^n)/(8^-n+3^-n)=24^n without using the logarith way?
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
(8^n + 3^n) / (8^-n + 3^-n)
work with the denominator
(8^-n + 3^-n) = (1/8^n + 3^n)
LCM is 24, therefore
(8^-n + 3^-n) = (3^n + 8^n) / 24^n
invert denominator and multiply by numerator
(8^n + 3^n) * 24^n / (8^n + 3^n) = 24^n
note that denominator and numerator cancels (8^n + 3^n)

RELATED QUESTIONS
How do you factor * n(n-3) +8(n-3)... (answered by MathLover1)

If 8^n=27, what is 4^n? I have worked out that 8^n/4^n=2^n, so the answer is 27/2^n, but (answered by Alan3354)

how do you solve: 8(2-n)-1=n+3(-5-1)+7n ... without getting a decimal or... (answered by ReadingBoosters)

The mean of the list n, n + 3, n+4, n+5, n+6, n+8, n+10, n + 12, n+15 is 11. What is... (answered by MathLover1,josgarithmetic)

3(n+7)=3-3(n-8) (answered by boilpoil)

m^8 *... (answered by TheProdicalSon)

3(8-n)+2 (answered by jim_thompson5910)

2(n+8)-3 (answered by edjones)

How do you figure this problem? 3/8 * n/n= 375/1000 (answered by Alan3354)