SOLUTION: If the average (arithmetic mean) of six numbers is 28 and the average of two of these numbers is 18, what is the average of the other four numbers? a) 29 b) 30 c) 31 d) 32 e)

Question 885833: If the average (arithmetic mean) of six numbers is 28 and the average of two of these numbers is 18, what is the average of the other four numbers?
a) 29
b) 30
c) 31
d) 32
e) 33
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
WITH CALCULATOR:
For the six numbers:
--->

For the two numbers averaging 18:
--->

The sum of the other four numbers is
, and the average of those four numbers is

IN MY HEAD:
Those two numbers averaging 18 are (on the average)
lower than average.
The units missing must have been made up by the other numbers
That means that the average of those other numbers must be
units higher than the average of all six numbers.
So the average of the other four numbers is

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