SOLUTION: FIND THE SUM OF TWO DIGIT NUMBERS WHICH BEING DIVIDED BY 4 LEAVE A REMAINDER OF 1. (ANS-1210)

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Question 866321: FIND THE SUM OF TWO DIGIT NUMBERS WHICH BEING DIVIDED BY 4 LEAVE A REMAINDER OF 1.
(ANS-1210)

Found 2 solutions by htmentor, MathLover1:
Answer by htmentor(1343)   (Show Source): You can put this solution on YOUR website!
The sequence of numbers divisible by 4, with a remainder of 1 are 5,9,13,17,21,...
The general formula for the nth term of this sequence is a_n = 4n + 1
The sum of the first n terms of an arithmetic sequence, S_n = (n/2)*(a_1 + a_n)
n=24 gives the largest two digit number, 97.
S_24 = (24/2)(5+97) = 1224. But the two digit numbers start with 13, so we need to subtract 5+9=14 from this sum
Ans: 1210

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
the number is of the form by definition where is a natural number
first such 2 digit number is
last such 2 digit number is

this is an arithmetic progression with common difference
so, we have ,,,,,,,,,,,,,,,,,,,,
the sum is given by
is the number of terms, is the first number, is the common difference





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