SOLUTION: 2y^2+4xy=x^2
Solve for y.
The book says the answer is y=x(-1+or- sqrt 6/2)
I can't get to the answer please help!
Algebra.Com
Question 842043: 2y^2+4xy=x^2
Solve for y.
The book says the answer is y=x(-1+or- sqrt 6/2)
I can't get to the answer please help!
Answer by josgarithmetic(39631) (Show Source): You can put this solution on YOUR website!
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