SOLUTION: When the length of a rectangle is increased by 20% and the width increased by
10%, by what percent is the area increased?
Algebra.Com
Question 833960: When the length of a rectangle is increased by 20% and the width increased by
10%, by what percent is the area increased?
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
Let l = length of original rectangle
Let w = width of original rectangle
Let a = lw = area of original rectangle
Let L = length of expanded rectangle
(1) L = l + 0.20*l or
(2) L = 1.20*l
Let W = width of expanded rectangle
(3) W = w + 0.10*w or
(4) W = 1.1*w
Let A = area of expanded rectangle
(5) A = L*W or
(6) A = (1.2l)*(1.1w) or
(7) A = (1.2*1.1)*lw or
(8) A = (1.32)*a or
(9) A = a + 0.32*a or
(10) A = a + 32% of a
Answer: The area of the expanded rectangle is 32% larger than the original rectangle.
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