Hi, there-- THE PROBLEM: On the first 3 exams of his geometry class, Luis got an average score of 81. What does he need on the next exam to have an overall average of 83? A SOLUTION: Let x be the score Luis needs on his next exam. The formula for finding the average score is [the sum of the scores] / [the number of scores] = [average score] Luis had an average of 81 after 3 exams, so we could work backwards from the average score to find the sum of his first three scores. We multiply 81*3=243. The sum of his first three scores is 243. To find his average score after 4 exams, Luis will add his 4th exam score to 243 and divide the sum by 4. Luis wants an overall score of 83. Let's write an equation for that. 243 + x is the sum of the first three score plus the score needs on his 4th exam. We divide by 4 because we are taking the average of 4 scores. Luis needs his average to equal 83. (243+x)/4 = 83 Solve for x. Multiply both sides by 4. 243 + x = 83 * 4 243 + x = 332 Subtract 243 from each side. x = 332 - 243 Simplify. x = 89 Luis needs a score of 89 on his 4th exam. Hope this helps! Mrs. Figgy math.in.the.vortex@gmail.com