Sir/Madam
Please help me solve the problem given below
The average of 8 numbers is 12.If one of them exceeds the average of remaining by
8.The number is ?
Thank you
Let number be N
Then sum, excluding N is: 96 N
Average of numbers, excluding N =
Therefore,
7N = 96 N + 56 ------ Multiplying by LCD, 7
7N + N = 96 + 56
8N = 152
N, or number = , or
You can do the check!!
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