SOLUTION: what is the perimeter of a semicircle with a rdius of 25ft
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Question 707846: what is the perimeter of a semicircle with a rdius of 25ft
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The circumference of this circle is 2*pi*25 = 50pi feet
Cut this in half to get 50pi/2 = 25pi
So the outer curved part of the semicircle is 25pi feet
The straight part of the semicircle is 25*2 = 50 feet.
So in total, the perimeter of the semicircle is 25pi + 50 feet
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