SOLUTION: kim had 78, 82, and 64 on her first three tests. What would be the lowest possible average on the next three exams so that Kim's grade in the class, based on the average of six ex

Algebra.Com
Question 651980: kim had 78, 82, and 64 on her first three tests. What would be the lowest possible average on the next three exams so that Kim's grade in the class, based on the average of six exams, is a least 80?
How can I set up an algebraic equation and please show you came to a solution.

Answer by rfer(16322)   (Show Source): You can put this solution on YOUR website!
(78+82+64+3x)/6=80
224+3x=80*6
224+3x=480
3x=480-224
3x=256
x=256/3
x=85.3

RELATED QUESTIONS

Rita has scored 64, 71, and 83 on her previous three tests. What score does she need on... (answered by oberobic)
Suppose your grades on your first four exams were 84%, 90%, 68%, and 89%. What would be... (answered by checkley77)
Suppose your grades on your first four exams were 78%, 87%, 68%, and 83%. What would be... (answered by Alan3354)
Pete had received grades of 76%, 83%, 93% on three algebra tests. What would he have to... (answered by JulietG)
Linda has scored 93 ,82 , and 72 on her previous three tests. What score does she need on (answered by stanbon,MathLover1)
laura has scored 64, 62 and 71 on her previous three tests. What score does she need on... (answered by rfer)
A student has scores of 83, 89, 78, and 86 on her first four tests. what score must she... (answered by scott8148)
Lisa has scored 64 , 86 , and 84 on her previous three tests. What score does... (answered by rfer,Alan3354)
Linda had scored 81 ,60 and 61 on her previous three tests what squirt that she needs... (answered by josgarithmetic)