SOLUTION: I have been working on this math problem for the past 2 hours and is having a difficult time with it. Can anyone please help me. p(x)= -.1x^2+50x-300, where x is the number of i

Question 580348: I have been working on this math problem for the past 2 hours and is having a difficult time with it. Can anyone please help me.
p(x)= -.1x^2+50x-300, where x is the number of items sold, x>0.
Please and thank you
Answer by dfrazzetto(283) (Show Source): You can put this solution on YOUR website!
p(x)= -.1x^2+50x-300, where x is the number of items sold, x>0.
what do you want to know? P given a certain value of x? or if P(x) = some value, find x??
You haven't asked a question yet.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=2380 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 6.07378164699064, 493.926218353009. Here's your graph:

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