SOLUTION: two investments were made totaling 8800 dollars. for a certain year these investments yielded 1326 dollars in simple intrest. part of the 8800 was ivested at 14% and part at 16%. F

Question 520672: two investments were made totaling 8800 dollars. for a certain year these investments yielded 1326 dollars in simple intrest. part of the 8800 was ivested at 14% and part at 16%. Find the amount invested in each rate
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
Amount invested at 14% = x
Amount invested at 16% = 8800-x
Given
Total interest on both investments = 1326
14% * (x) + 16% * (8800-x) = 1326
14/100 * (x) + 16/100 * (8800-x) = 1326
Multiply by 100 both sides
14 * (x) + 16 * (8800-x) = 1326 * 100
14x + 140800-16x = 132600
-2x=132600-140800
-2x=-8200
-2x/-2=-8200/-2
x=4100
Amount invested at 14% = x = 4100
Amount invested at 16% = 8800-x = 8800-4100 = 4700

Check
=====
4100 * 14/100 + 4700 * 16/100 = 1326
Multiply by 100 both sides
4100*14 + 4700*16 = 132600
57400+75200=132600
132600=132600
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