SOLUTION: An instrument store gives a 10% discount to all students off the original cost of an instrument. During a back to school sale an additional 15% is taken off the discounted price. J

Question 457035: An instrument store gives a 10% discount to all students off the original cost of an instrument. During a back to school sale an additional 15% is taken off the discounted price. Julie, a student at the local high school, purchases a flute for $306. How much did it originally cost?

I know this is simple I am just having trouble remembering how to convert percentages and how to solve the problem. Please help me with the steps involved in this problem. Thank you Kevin.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
10% discount means she paid 90%=.90
15% discount means she paid 85%=.85
x is the original price
.85*(.90*x)=306
x=400
check
.90*400=360
.85*360=306
ok

RELATED QUESTIONS
An instrument store gives a 10% discount to all students off the original cost of an... (answered by ewatrrr)

An instrument store gives a 10% discount to all students off the original cost of an... (answered by solver91311)

An instrument store gives a 10% discount to all students off the original cost of an... (answered by rfer)

An instrument store gives a 10% discount to all students off the original cost of an... (answered by drk)

1. An instrument store gives a 10% discount to all students off the original cost of an... (answered by Theo,richwmiller)

An instrument store gives a 10% discount to all students off the original cost of an... (answered by josmiceli,richwmiller)

An instrument store gives a 10% discount to all students off the original cost of an... (answered by mananth)

An instrument store gives a 10% discount to all students off the original cost of an... (answered by ikleyn)

An instrument store gives a 10% discount to all students off the original cost of an... (answered by checkley71,josmiceli)

I can't seem to come up with the answer that I'm given, but would like to know how to... (answered by ankor@dixie-net.com)