SOLUTION: The side length of a square is (8+2x) units. The area of this square is the same as the perimeter of another square with a side length of (x^2 + 48) units. Find the value of x.

Question 399128: The side length of a square is (8+2x) units. The area of this square is the same as the perimeter of another square with a side length of (x^2 + 48) units. Find the value of x.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
The side length of a square is (8+2x) units. The area of this square is the same as the perimeter of another square with a side length of (x^2 + 48) units. Find the value of x.
Length = (8+2x)
Area = (8+2x)^2
Area = 64+32x+4x^2
..
Side = (x^2+48)
Perimeter = 4 * (x^2+48)
=4x^2+192
...
4x^2+192=4x^2+32x+64
32x=192-64
32x=128
/4
x=4

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