SOLUTION: 2^x-2^(-x)=4

Algebra.Com
Question 368115: 2^x-2^(-x)=4
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
2^x-2^(-x)=4
Multiply by 2^x
2^(2x) - 1 = 4*2^x
Sub y for 2^x
y^2 - 1 = 4y
y^2 - 4y - 1 = 0
-------------------
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=20 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 4.23606797749979, -0.23606797749979. Here's your graph:

y = 1 ± sqrt(5)
2^x = 1 + sqrt(5) --- Ignore the negative answer
x*log(2) = log(1 + sqrt(5))
x = log(1 + sqrt(5))/log(2)
x =~ 1.69242

RELATED QUESTIONS

x^2+x-4 (answered by checkley75)
... (answered by checkley71)
x(x-2)=4 (answered by jojo14344,Fombitz)
x/2 + x/4... (answered by drj)
x + 4 = -2 +... (answered by stanbon)
x^2-4/x (answered by Alan3354)
X+2=x __... (answered by solver91311)
2+x=4,x=? (answered by lynnlo)
x+4=|x-2| (answered by Alan3354)
(x+2)(x+4) (answered by addingup)