SOLUTION: A basketball team won two out of their last four games. In how many different orders could they have two wins and two losses in the four games?

Question 317156: A basketball team won two out of their last four games. In how many different orders could they have two wins and two losses in the four games?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A basketball team won two out of their last four games. In how many different orders could they have two wins and two losses in the four games?
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The is number of ways to arrange aabb where a=win and b=lose
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# of arrangements = 4!/(2!*2!) = 24/4 = 6
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Cheers,
Stan H.
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