SOLUTION: Consider system of equations. Y=ax^2+bx+c Y=nx^2+mx+p Suppose the parabolas have the same axis of symmetry.How many possible solution does the system have? Explain

Question 252148: Consider system of equations.
Y=ax^2+bx+c
Y=nx^2+mx+p
Suppose the parabolas have the same axis of symmetry.How many possible solution does the system have? Explain
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Consider system of equations.
Y=ax^2+bx+c
axis: -b/(2a)
Y=nx^2+mx+p
axis: -m/(2n)
Suppose the parabolas have the same axis of symmetry.How many possible solution does the system have? Explain
Equation:
-b/2a = -m/2n
-bn = -am
am - bn = 0
--------------------
Comment:
Using Cramer's method you would find
that the coefficient determinant is am-bn.
When it equals zero the solution values are undefined.
---
The system has no solutions.
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Cheers,
Stan H.
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