SOLUTION: x-4/(x+1) - 10/(x^2-1) = 0
(x-4)(x-1)-10/(x^2-1)=0
x^2-5x-6/(x^2-1)=0
how do i go from here to find and check all proposed solutions.
Algebra.Com
Question 193467: x-4/(x+1) - 10/(x^2-1) = 0
(x-4)(x-1)-10/(x^2-1)=0
x^2-5x-6/(x^2-1)=0
how do i go from here to find and check all proposed solutions.
Answer by radikrr(7) (Show Source): You can put this solution on YOUR website!
(x-4)/(x+1)-10/(x-1)(x+1)=0
(x^2-5x+4-10)/(x+1)(x-1)=0
(x^2-5x+4-10)/(x+1)(x-1)=0
(x2-5x-6)(x+1)(x-1)=0
(x-6)(x+1)/(x+1)(x-1)=0
(x-6)/(x-1)=0
x-6=0
x=6
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