SOLUTION: 18z+45+z^(2 ) How do I factor this polynomial?

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Question 175242: 18z+45+z^(2 )
How do I factor this polynomial?

Found 2 solutions by jim_thompson5910, gonzo:
Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
18z%2B45%2Bz%5E2 Start with the given polynomial


z%5E2%2B18z%2B45 Rearrange the terms in descending order.


Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)
In order to factor z%5E2%2B18%2Az%2B45, first multiply the leading coefficient 1 and the last term 45 to get 45. Now we need to ask ourselves: What two numbers multiply to 45 and add to 18? Lets find out by listing all of the possible factors of 45


Factors:

1,3,5,9,15,45,

-1,-3,-5,-9,-15,-45, List the negative factors as well. This will allow us to find all possible combinations

These factors pair up to multiply to 45.

1*45=45

3*15=45

5*9=45

(-1)*(-45)=45

(-3)*(-15)=45

(-5)*(-9)=45

note: remember two negative numbers multiplied together make a positive number

Now which of these pairs add to 18? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 18

||||||
First Number|Second Number|Sum
1|45|1+45=46
3|15|3+15=18
5|9|5+9=14
-1|-45|-1+(-45)=-46
-3|-15|-3+(-15)=-18
-5|-9|-5+(-9)=-14


We can see from the table that 3 and 15 add to 18. So the two numbers that multiply to 45 and add to 18 are: 3 and 15

So the original quadratic


z%5E2%2B18%2Az%2B45


breaks down to this (just replace 18%2Az with the two numbers that multiply to 45 and add to 18, which are: 3 and 15)


z%5E2%2Bhighlight%283z%2B15z%29%2B45 Replace 18%2Az with 3z%2B15z

Group the first two terms together and the last two terms together like this:

%28z%5E2%2B3z%29%2B%2815z%2B45%29

Factor a 1z out of the first group and factor a 15 out of the second group.


1z%28z%2B3%29%2B15%28z%2B3%29


Now since we have a common term z%2B3 we can combine the two terms.


%28z%2B15%29%28z%2B3%29 Combine like terms.
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Answer:


So the quadratic z%5E2%2B18%2Az%2B45 factors to %28z%2B15%29%28z%2B3%29




Notice how %28z%2B15%29%28z%2B3%29 foils back to our original problem z%5E2%2B18%2Az%2B45. This verifies our answer.

Answer by gonzo(654) About Me  (Show Source):
You can put this solution on YOUR website!
you look for factors of 45 that will add up to 18.
45 = 9*5 the sum of which is 9 + 5 = 14 (no good)
45 = 3*15 the sum of which is 3 + 15 = 18 (good)
your factors are:
(z+15) * (z+3)
you multiply these together to get:
z^2 + 18z + 45
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