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You invested $24 comma 00024,000 in two accounts paying 5 %5% and 7 %7% annual interest, respectively.
If the total interest earned for the year was $1400, how much was invested at each rate?
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Let x dollars be the amount invested at 7%.
then the amount invested at 5% is (24000-x) dollars.
Write equation for the total annual interest
0.07x + 0.05*(24000-x) = 1400 dollars.
Simplify and find x
0.07x + 0.05*24000 - 0.05x = 1400
0.07x - 0.05x = 1400 - 0.05*24000
0.02x = 200
x = 200/0.02 = 20000/2 = 10000.
ANSWER. $10000 invested at 7%, the rest, or 24000-10000 = 14000 dollars invested at 5%.
CHECK. 0.07*10000 + 0.05*14000 = 1400 dollars, the combined annual interest. ! correct !
Solved.