SOLUTION: write the equation without fractions: 3+a/2a=1/3+5/6a.
a. 3+a=1+5
b. 9+3a=2a+5
c.2a=3+6a
d.2a^2=3a+6a^2
Algebra.Com
Question 1162560: write the equation without fractions: 3+a/2a=1/3+5/6a.
a. 3+a=1+5
b. 9+3a=2a+5
c.2a=3+6a
d.2a^2=3a+6a^2
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
.........cross multiply
.......simplify
answer is:
b.
RELATED QUESTIONS
5/2a +1/6a... (answered by Maths68,IFY)
Solve linear equation:... (answered by jainpreeja)
Solve for a.
6a(a+3) =... (answered by jim_thompson5910)
Factor.3a^2(a-b)-6a(a-b)+21(a-b)
Please assist me with the proper way to do this... (answered by solver91311)
Find the quotient.
12a^3p^4 ÷ -2a^2p
A.)-6a^3p^5
B.)-24ap^3
C.)-6ap^3
D.)6a^5p^3
(answered by Alan3354)
factor 3a^2(a-b)-6a(a-b)+21(a-b)
A) 3(a-b)(a^2-2a+7)
B) (3a-b)(a^2-2a+7)
C)... (answered by stanbon)
Is this problem factored completely correctly?
3a^3+6a^2-2a-4
(3a^3)+(-2a-4)... (answered by scott8148)
Hi everyone,
please help me last math problem.
Add:... (answered by Edwin McCravy)
I need to factor and I do not understand this equation, please help... (answered by stanbon)