SOLUTION: The product of two consecutive integers is 5 less than the square of the lesser integer. Find the greater of the two integers.

Question 1145373: The product of two consecutive integers is 5 less than the square of the lesser integer. Find the greater of the two integers.
Found 2 solutions by richwmiller, ikleyn:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Oops! I read 2 consecutive even integers!

Answer by ikleyn(52835) (Show Source): You can put this solution on YOUR website!
.

x*(x+1) = x^2 - 5 x^2 + x = x^2 - 5 x = -5 is the lesser number. x = -4 is your ANSWER. CHECK. a) (-5)*(-4) = 20. b) (-5)*(-5) - 5 = 25 - 5 = 20. ! Correct !

Solved, answered and completed. And explained.

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