SOLUTION: Luke hiked up a 41/2-mile trail to the top of Mt. Washington at an average speed of 21/7 mph. His dad hiked the same trail at an average speed of 21/4 mph. If Luke’s dad reaches

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Question 1139149: Luke hiked up a 41/2-mile trail to the top of Mt. Washington at an average speed of 21/7 mph. His dad hiked the same trail at an average speed of 21/4 mph. If Luke’s dad reaches the top of the mountain at noon, at what time will Luke arrive?
Found 3 solutions by Boreal, josgarithmetic, ikleyn:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
4.5=9/2
9/2 divided by 15/7, which is 2 1/7 is 9/2*7/15=63/30 or 2.1 hours
9/2 divided by 9/4, which is 2 1/4 is 9/2*4/9=2 hours
Luke arrives 0.1 hour later or 6 minutes after noon.
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
              SPEED            TIME           DISTANCE

Luke                                     

Dad

Time quantities easily filled in, . 
              SPEED            TIME           DISTANCE

Luke                                   

Dad

The extra time Luke needed compared to his dad, . If dad reached top at noon, then Luke reached top hours later, or 0.64286 hour, or 39 minutes.
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.

In the future, when you post to this forum, NEVER write 41/2,


since different people will read and interpret it DIFFERENTLY.


One will interpret as  ;  the other will read  .


Write 4 1/2 in this case, using the "blank" symbol between the integer part and the fraction.


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