SOLUTION: Please help me understand to solve these 3 problems (Algebra 2 factor grouping) 1) 3x^3-12x^2-2x+8 2) 4x^4 - 16x^2 - 9x^2+36 3) 2x^5 - 18x^3-3x^2+27

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Question 1132002: Please help me understand to solve these 3 problems (Algebra 2 factor grouping)
1) 3x^3-12x^2-2x+8
2) 4x^4 - 16x^2 - 9x^2+36
3) 2x^5 - 18x^3-3x^2+27

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
1)  3x^3 - 12x^2 - 2x + 8 = 


        Apply grouping.   Look: there are coefficients (3,-12) at x^3 and x^2    -  and  (-2,8)  at x  and the constant term.
        It gives you an idea how to group:


    3x^3 - 12x^2 - 2x + 8 = (3x^3 - 12x^2) - (2x -8) = 3x^2*(x-4) - 2*(x-4)


        Now use that (x-4) is the common factor


    = (x-4)*(3x^2 - 2).


    Thus this factoring is COMPLETED over the polynomials with integer coefficients.



2)  4x^4  - 16x^2 - 9x^2 + 36


        THE SAME IDEA WORKS again:


    4x^4  - 16x^2 - 9x^2 + 36 = (4x^4  - 16x^2) - (9x^2 - 36) = 4x^2*(x^2-4) - 9*(x^2-4) = (x^2-4)*(4x^2-9) = (x-2)*(x+2)*(2x-3)*(2x+3).


Let me leave the  " #3 "  for you to complete it on your own - use  THE  SAME  IDEAS !


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Is everything clear to you ?


If you still have questions,  let me know.



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