SOLUTION: The stage of a rocket burns 28s longer than the second stage. If the total burning time for both stages is 152 s how long does each stage burn?

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Question 1121843: The stage of a rocket burns 28s longer than the second stage. If the total burning time for both stages is 152 s how long does each stage burn?
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52908)   (Show Source): You can put this solution on YOUR website!
.
The stage of a rocket burns 28 s longer than the second stage.
If the total burning time for both stages is 152 s how long does each stage burn?
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From the condition, you have these two equations


x + y = 152    (1)   (x = the first stage burning time)
x - y = 28     (2)


Add the two equations. You will get  


2x = 152 + 28 = 180  ====>  x = 90 seconds for the first stage.


Then y = 152 - 90 = 62 seconds for the seconf stage.


Solved.


Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = burn time in sec for 2nd stage
= burn time for 1st stage
覧覧-



And

覧覧覧覧-
1st stage: 90 sec
2nd stage: 62 sec

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