SOLUTION: A train leaves San Diego at 3:00 PM. A second train leaves the same city in the same direction at 7:00 PM. The second train travels 56 mph faster than the first. If the second trai

Question 1017189: A train leaves San Diego at 3:00 PM. A second train leaves the same city in the same direction at 7:00 PM. The second train travels 56 mph faster than the first. If the second train overtakes the first at 10:00 PM, what is the speed of each of the two trains?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the speed in mi/hr of the 1st train
= the speed in mi/hr of the 2nd train
---------------------
What is the head start of the 1st train in miles?
( 3PM to 7 PM is 4 hrs )
---------------------
Let = distance in miles the 2nd train
travels until it catches up with 1st train
= time in hrs from 7 PM to 10 PM, so
hrs
-------------------------------------
Equation for 1st train:
(1)
Equation for 2nd train:
(2)
--------------------
(1)
(1)
and
(2)
--------------------

and

---------------
The 1st train's speed is 42 mi/hr
The 2nd train's speed is 98 mi/hr
----------------------------
check:
(1)
(1)
(1)
(1) mi
and
(2)
(2)
(2) mi
OK

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