SOLUTION: The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the

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Question 962394: The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the measure of angle B. Find the measure of each angle.

Thank you for your help. It helps me a lot to solve this problem.
Found 2 solutions by macston, MathTherapy:
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
.
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A=C-20; C=2B
2B=C
B=C/2
A+B+C=180 Substitute for A and B.
(C-20)+(C/2)+C=180
2.5C-20=180 Add 20 to each side.
2.5C=200 Divide each side by 2.5.
C=80 ANSWER 1: Angle C is 80 degrees.
B=C/2=80/2=40 ANSWER 2: Angle B is 40 degrees.
A=C-20=80-20=60 ANSWER 3: Angle A is 60 degrees.
CHECK:
A+B+C=180 degrees
60 degrees+40 degrees+80 degrees=180 degrees
180 degrees=180 degrees


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the measure of angle B. Find the measure of each angle.

Thank you for your help. It helps me a lot to solve this problem.
Let measure of ∠B be B

Then measure of ∠C is: 2B

Measure of ∠A is: 2B - 20

Therefore, we get: B + 2B + 2B - 20 = 180

5B = 200

∠B measures: , or 

∠C measures: , or 

∠A measures: , or  

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