SOLUTION: Two angles are complementary. One angle is 12degrees larger than the other . Using two variables x and y, find the size of each angle by solving a system of equations.
When I w
Algebra.Com
Question 939951: Two angles are complementary. One angle is 12degrees larger than the other . Using two variables x and y, find the size of each angle by solving a system of equations.
When I was trying to figure this out I got the answer x=51 and y=39
I don't think that is write....
Can you show me how to this equation should be wrote out please and thank you
Jeanine
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two angles are complementary. One angle is 12degrees larger than the other . Using two variables x and y, find the size of each angle by solving a system of equations.
-------
Equations::
x + y = 90 degrees
x = y + 12
-------
Substitute for "x" and solve for "y"::
y+12 + y = 90
2y = 78
y = 39 degrees
----
x = 90-y = 90-39 = 51 degrees
------------
You are correct.
Cheers,
Stan H.
RELATED QUESTIONS
two angles are complementary. one angle is 12 degree larger than the other. using two... (answered by nerdybill)
Two angles are supplementary. One angle measures 12degrees more than the other. Find the... (answered by praseenakos@yahoo.com)
two angles are supplementary, one angle is 24 degrees more than twice the other. using... (answered by cleomenius)
Find two complementary angles where one is 12 degrees larger than the other angle. (answered by rfer,MathLover1)
One of two complementary angles is 2 less than three times the other angle. Find the... (answered by nerdybill)
two angles are complementary. one angle is 81degree less than twice the other. find the... (answered by ewatrrr)
two angles are complementary one angle is 20° less than the other angle find the... (answered by rfer)
two angles are adjacent and complementary. one angle measure is twice as larger as the... (answered by rfer)
Two angles are complementary. One of the angles is 8 degrees more than half the other.... (answered by tommyt3rd)