SOLUTION: How do you find an exterior angle when all you know is ABC + BCA + CAB = 180 5x + 8 + 6x + 22 + 3x - 25 = 180 14x =175 x = 12.5 M<BAC = 5X+8 = 70.5 M<ABC=6X+22 = 97 M<BCA=3X-25 = 1

Question 924549: How do you find an exterior angle when all you know is ABC + BCA + CAB = 180 5x + 8 + 6x + 22 + 3x - 25 = 180 14x =175 x = 12.5 M
Answer by MathLover1(20855) (Show Source): You can put this solution on YOUR website!
you know is
you also know it's a triangle

you know

measure of each angle is:
M<
M<
M<
you also know that an measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles
let's exterior angles be , , and (the letter of each vertex)
then
M< =M< =>M< =>M<
M< =M< =>M< =>M<
M< =M< =>M< =>M<

or, solve it using the sum of an exterior angle and its corresponding interior angle which is
exterior angle and sum up to
so,

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