SOLUTION: 1. The points A(-3,5) and B(2,4) are on a circle whose center is at O(1,c). (i) Find two expressions for the radius of this circle. (ii) Now find the exact value c. [Hint: Bot

Algebra.Com
Question 915363: 1. The points A(-3,5) and B(2,4) are on a circle whose center is at O(1,c).
(i) Find two expressions for the radius of this circle.
(ii) Now find the exact value c. [Hint: Both points are the same distance from O.]
(iii) Write the equation of this circle.
(iv) Find any x- or y-intercepts of this circle. Explain algebraically your steps, and write a complete sentence explanation about the intercepts. Discuss both x and y!
(v) Now sketch this circle on graph paper. Label the points A, B, O and those you found in (iv), on your sketch.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
A(-3,5)
O(1, c)
.......
B(2,4)
O(1, c)
...Distance Equal
16 + (5-c)^2 = 1 + (4-c)^2
16 + 25 - 10c + C^2 = 1 + 14 -8c + c^2
26 = 2c
13 = c
.........
B(2,4)
O(1, 13) r = sqrt( 1 + 81) = sqrt(82)
y-intercept (0,22), x-intercept: none


RELATED QUESTIONS

Show that the points (-2,5),(-2,-1) and (4,-1) all lie on a circle whose center is at... (answered by Mathtut)
Hello, could you help me with this problem: Points A (2,3), B (- 2, 5), and C(4,-1) all... (answered by josgarithmetic)
The points (2, 5) and (4, –1) are endpoints of the diameter of a circle. (a) State... (answered by Fombitz)
show rhat the points A(-2,2) B(5,-5) C(4,2) are located on a circle with center w(1,-2) . (answered by Alan3354)
plz solve this problem for me_ Show that the points 3+2i,2-i,1+i,4+i lies on a circle.... (answered by Alan3354)
show that the points (-2, 5), (-2, -1) and (4, -1) all lie on a circle whose is at (1,... (answered by richwmiller)
find the equation of a circle whose center is at (2, -4) and radius... (answered by Alan3354)
Question-1: (a): Let be the line given by the equation 3x+4y+12=0 . Find the... (answered by richwmiller)
show that the points (-2,5), (-2,-1) and (4,-1) all lie on a circle whose radius... (answered by josgarithmetic)