SOLUTION: pg. 166. One of two complementary angles measures 30 degrees more than three times the other. Find the measure of each angle.

Question 91403This question is from textbook Glencoe Algebra 1
: pg. 166. One of two complementary angles measures 30 degrees more than three times the other. Find the measure of each angle.This question is from textbook Glencoe Algebra 1

Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website!
X+Y=90 OR X=90-Y
X=3Y+30 NOW SUBSTITUTE (90-Y) FOR X & SOLVE FOR Y
90-Y=3Y+30
-Y-3Y=30-90
-4Y=-60
Y=-60/-4
Y=15 ANSWER.
X=3*15+30
X=45+30
X=75 ANSWER.
PROOF
15+75=90
90=90

Answer by stanbon(48516) (Show Source):
You can put this solution on YOUR website!
One of two complementary angles measures 30 degrees more than three times the other. Find the measure of each angle.
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Let one of the angles have measure "x"
The other has measure "90-x"
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EQUATION:
90-x = 3x+30
4x = 60
x = 15 degrees (one of the angles)
90-x = 90-15 = 75 degrees (the complementary angle)
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Cheers,
Stan H.