SOLUTION: You are flying a kite with 50 feet of string extended. Due to the wind, the angle of elevation is equal to 50 degrees How high is the kite above the ground adding my own holding h

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Question 818223: You are flying a kite with 50 feet of string extended. Due to the wind, the angle of elevation is equal to 50 degrees How high is the kite above the ground adding my own holding height?
Answer by Edwin McCravy(20059)   (Show Source): You can put this solution on YOUR website!

The kite is at point K.  Your hand is at point H.

I will assume you are holding the string 5 feet above the ground
at point H.  If that's not your height change it to your height.

We want to find JK and then we'll add 5 feet to that.

JK is the opposite side of the 50° angle in right triangle HJK.  
The kite string HK = 50 feet is the hypotenuse of right triangle HJK.

The trig ratio that involves the opposite side and the hypotenuse
is the sine, which is 

sin(50°) = 

sin(50°) = 

Multiply both sides by 50

50sin(50°) = JK

50(.7660444431) = JK
38.30222216 = JK

So adding your holding height, (between J and the ground, which is
also 5 feet, gives 43.30222216 feet.  Round to however many decimal
places you were told to round.  To the nearest foot is 43 feet.

Edwin
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