SOLUTION: the diagonals of a square pqsr intersect at e. if pe=2x+6 and rq=6x-10, find the value of x
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Question 736287: the diagonals of a square pqsr intersect at e. if pe=2x+6 and rq=6x-10, find the value of x
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Since it is a square, the two diagonals bisect each other and therefore PE is one half of RQ.
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Solve for 
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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