SOLUTION: what is the answer of this questions: 1.) (-3-3√3)^2 2.) 5 �i 3.) 1�(2i-3) 4.)(3+2i�(2-i) 5.) (3+ 2i) � 4 6.) 1 � ( 3+ √-2)

Question 666452: what is the answer of this questions:
1.) (-3-3√3)^2
2.) 5 �i
3.) 1�(2i-3)
4.)(3+2i�(2-i)
5.) (3+ 2i) � 4
6.) 1 � ( 3+ √-2)
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
1) (-3-3sqrt(3))^2 = (-3)^2*(1+sqrt(3))^2 = 9*(1+2*sqrt(3) +3) = 18*(2+sqrt(3))
2) 5/i = 5*i/i*i = 5i/(-1) = -5i
3) 1/(2i-3) = (2i+3)/((2i-3)*(2i+3)) = (2i+3)/(-4+2i-2i-9) = (2i+3)/(-13) = -3/13 - (2/13)i
4) 3+(2i)/(2-i) = 3+(2i)(2+i)/(2-i)(2+i) = 3 + 2i(2+i)/5 = 3+(4i-2)/5 = (13+4i)/5 = 13/5 + (4/5)i
5) (3+2i)/4 = 3/4 + i/2
6) 1/(3+sqrt(-2)) = 1/(3+i*sqrt(2)) = (3-i*sqrt(2))/((3+i*sqrt(2))*(3-i*sqrt(2))) = (3-i*sqrt(2))/(9+2) = 3/11 - i*(sqrt(2))/11
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SOLUTION: what is the answer of this questions: 1.) (-3-3&#8730;3)^2 2.) 5 �i 3.) 1�(2i-3) 4.)(3+2i�(2-i) 5.) (3+ 2i) � 4 6.) 1 � ( 3+ &#8730;-2)

SOLUTION: what is the answer of this questions: 1.) (-3-3√3)^2 2.) 5 �i 3.) 1�(2i-3) 4.)(3+2i�(2-i) 5.) (3+ 2i) � 4 6.) 1 � ( 3+ √-2)