SOLUTION: A and B are supplementary angles. mA is 6° less than twice mB. Find mA and mB.

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Question 651569: A and B are supplementary angles. mA is 6° less than twice mB. Find mA and mB.
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(57282) About Me  (Show Source):
You can put this solution on YOUR website!
A and B are supplementary angles. mA is 6° less than twice mB. Find mA and mB.
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Let mA = 180-x
Then mB = x
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Equation:
180-x = 2x-6
3x = 186
x = 31 degrees (measure of B)
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180-x = 180-31 = 149 degrees (measure of A)
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Cheers,
Stan H.

Answer by MathTherapy(1422) About Me  (Show Source):
You can put this solution on YOUR website!

A and B are supplementary angles. mA is 6° less than twice mB. Find mA and mB.

Since the angles are supplementary, then angle B = 180 - A

We then have: A = 2(180 - A) - 6

A = 360 - 2A - 6

A + 2A = 354

3A = 354

Angle A = 354%2F3, or highlight_green%28118%5Eo%29

Angle B = 180 - 118, or highlight_green%2862%5Eo%29

You can do the check!!

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