SOLUTION: What is the measures of two complementary angles such that the larger angle is six less than twice the smaller angle? My solution is: Complementary angle= 90 2x-6=90 2x=90+6 2

Question 628518: What is the measures of two complementary angles such that the larger angle is six less than twice the smaller angle?
My solution is:
Complementary angle= 90
2x-6=90
2x=90+6
2x=96
1/2(2x)=(96)1/2
x=48
Small Complementary Angle = 48
Larger Complementary Angle = 96
Answer by John10(297) (Show Source): You can put this solution on YOUR website!
What is the measures of two complementary angles such that the larger angle is six less than twice the smaller angle?
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Let x be the smaller angle and y be the bigger angle
x + y = 90 ( sum of complementary angles is 90 degrees)
y = 2x - 6
Substitute the second equation into the first equation for y:
x + (2x - 6) = 90
3x - 6 = 90
3x = 96
x = 96/3
x = 32
y = 2(32) - 6 = 64 - 6 = 58
So the small angle is 32 degrees
The large angle is 58 degrees.
Hope it helps:)
John10
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