SOLUTION: Given two parallel lines with a transversal, if one of the angles measure 50 degrees, find the measures of all the other angles. Explain how you found those angles.

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Question 618363: Given two parallel lines with a transversal, if one of the angles measure 50 degrees, find the measures of all the other angles. Explain how you found those angles.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Angles 2, 4, 6, and 8 measure 50%5Eo, the other angles measure
180%5Eo-50%5Eo=130%5Eo

THE REASONS (one of many ways to justify the conclusions):
I made the drawing so that the measure of angle 2 would be 50%5Eo.
As for the other angles, we apply what was learned in geometry class:
Angles opposed "tip to tip", like the pair 2 and 4, and the pair 6 and 8, are called vertical and are congruent (same measure). So angle 4 measures 50%5Eo because it is vertical to angle 2.
Angles in between the parallel lines, but on different sides of the transversal, like the pair of 4 and 6, are called alternate interior, and are also congruent. So angle 6 measures 50%5Eo because it is alternate interior to angle 4.
And angle 8, vertical to 6, also measures 50%5Eo.
Each of the other angles is supplementary to a 50%5Eo angle, and must measure 130%5Eo because a pair of supplementary angles must add to 180%5Eo.
NOTE:
There are different ways to explain the same conclusions. For example, you could say that angle 1 is suplementary to angle 2, or that it is supplementary to angle 4; it works one way or the other. You pick one, no need to say it both ways. Something similar happens for angles 3, 5, and 7.