SOLUTION: the sides of an acute triangle are x, 35, and 37, where x is the shortest side.find the range of possible values for x and express it as an inequality. pleases help. i have no ide

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Question 564641: the sides of an acute triangle are x, 35, and 37, where x is the shortest side.find the range of possible values for x and express it as an inequality.
pleases help. i have no idea where to start with this. thanks in advance for your help.
Answer by josmiceli(9817) About Me  (Show Source):
You can put this solution on YOUR website!
Imagine the side that is +37+ laying flat
on a table. The side that is +35+ is hinged
at one end of the +37+. It is free to swing
in a plane that is perpendicular to the table.
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If you lay it alongside the +37+ side, the
difference is +2+, so +x+%3E+2+ is one limit.
-----------------------------------
As I swing the +35+ side I must stop before
the distance from the free end of 35 and
the unhinged end of 37 equals +35+,
because x must be the shortest side
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So, the limits are +2+%3C+x+%3C+35+
Hope this isn't confusing